Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.7 Substitution Method - Exercises - Page 275: 27


$$\frac{1}{40}( 4x+5)^{10}$$

Work Step by Step

Given $$ \int(4 x+5)^{9} d x$$ Let $$ u= 4x+9\ \ \ \Rightarrow\ \ du=4dx$$ Then \begin{align*} \int(4 x+5)^{9} d x&=\frac{1}{4}\int u^{9} d u\\ &=\frac{1}{40}u^{10}\\ &= \frac{1}{40}( 4x+5)^{10} \end{align*}
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