Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 4 - Applications of the Derivative - 4.2 Extreme Values - Exercises - Page 180: 5


6 and -3.

Work Step by Step

$ f'(x)$ exists for all x. Therefore, the only critical points are the solutions of $ f′(x)=0$ $ f'(x)=3x^{2}-9x-54=0$ Or $ x^{2}-3x-18=0$ $\implies x= 6$ or $ x=-3$ Thus, the critical points are the roots $ c=6$ and $ c=-3$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.