Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 4 - Applications of the Derivative - 4.2 Extreme Values - Exercises - Page 180: 4

Answer

None.

Work Step by Step

Let x be the critical point. This implies f'(x)=0 or f is not differentiable. The function f which is a linear function is differentiable at every point. Also f'(x)= $\frac{d}{dx}(7x-2)= 7$ ⇒ f'(x)≠0. Thus f(x)=7x-2 has no critical points.
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