$\Delta f= 0.12$
Work Step by Step
$\Delta f= f(a+\Delta x)-f(a)=f(3.02)-f(3)$ $\implies a=3$ and $\Delta x= 0.02$ According to the Eq.2, $\Delta f= f'(a)\Delta x= f'(3)\times0.02$ $= 2\times3\times0.02= 0.12$
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