Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.7 The Chain Rule - Exercises - Page 147: 89



Work Step by Step

$\frac{d}{dx}(g(\sqrt x))=g'(\sqrt x)\times\frac{d}{dx}\sqrt x$ $=g'(\sqrt x)\times\frac{1}{2\sqrt x}$ $\frac{d}{dx}(g\sqrt x)|_{x=16}=g'(\sqrt {16})\times\frac{1}{2\sqrt {16}}$ $=g'(4)\times\frac{1}{2\times4}=\frac{1}{2}\times\frac{1}{8}=\frac{1}{16}$
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