Answer
$-\frac{11\pi}{360}$ $rad/min$
Work Step by Step
The minute hand moves at a rate of $\frac{2\pi}{60}$ = $\frac{\pi}{30}$ $rad/min$
The hour hand makes one-twelfth of a revolution every 60 minutes, so the hour hand moves with a rate of $\frac{\pi}{360}$ $rad/min$
$θ'(t)$ = $\frac{\pi}{360}-\frac{\pi}{30}$ = $-\frac{11\pi}{360}$ $rad/min$
