Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.4 Rates of Change - Exercises - Page 130: 28

Answer

The bucket was dropped from the top of the 15th floor.

Work Step by Step

let $H$ = height $t$ = time $s(t)$ = the height of the bucket at time t $s(t)$ = $H - 4.9t^{2}$ t = T-1.5, s(t) = 47.5 m $s(T-1.5)$ = $H - 4.9(T-1.5)^{2}$ $47.5$ = $H - 4.9(T-1.5)^{2}$ => equation 1 t = T, s(t) = 0 m $s(T)$ = $H - 4.9(T)^{2}$ $0$ = $H - 4.9(T)^{2}$ => equation 2 solve 2 equations then T = 3.98 and H = 77.67 m Floor is 5 m high so Floor = $\frac{77.67}{5}$ = $15.53$ so The bucket was dropped from the top of the 15th floor.
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