Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.3 Product and Quotient Rules - Preliminary Questions - Page 121: 2


$(\frac{f}{g})'(1) = -1$

Work Step by Step

We know that: $(\frac{f}{g})' = \frac{gf' - fg'}{g^2}$ By substituting the values we are given, we get: $(\frac{f}{g})'(1) = \frac{2*2 - 2*4}{2^2}$ Which can then simplify to: $(\frac{f}{g})'(1) = -1$
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