## Calculus (3rd Edition)

(a) The statement is false. The correct version is: $fg$ denotes the function whose value at $x$ is $f(x)g(x)$ (b) True. The notation $f/g$ means that we divide two functions. (c) False. Derivative of $fg$ is not equal to $f'g'$, but is equal to $f'g+g'f$ (d) False. According to the product rule, we have $(fg)'(4)=f'(4)g(4)+g'(4)f(4)$ (e) True.