Work Step by Step
Equation of the tangent line at a point a is of the form $y-f(a)=f'(a)(x-a)$ In this case, $a=3, f(a)=5$ and $f'(a)=2$. Therefore, the equation of the given tangent line is $y-5=2(x-3)$ or $y=2x-1$
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