Answer
$f'(1)=0$
$f'(2)= 0.8$
Work Step by Step
From the given figure, we can see that:
The tangent line at $x= 1$ is horizontal, so $f'(1)= 0$
To find $f'(2) $, we find two points on the tangent line, for instance $ ( 2,2) $ and $( 2.5 ,2.4)$:
\begin{align*}
f'(2)&\approx \frac{2.4-2}{2.5-2}\\
&\approx 0.8
\end{align*}
