Answer
$\infty$
Work Step by Step
We evaluate the limit:
\begin{aligned}
\lim _{x \rightarrow 5^{+}} \frac{x^{2}-24}{x^{2}-25} &=\frac{\lim _{x \rightarrow 5^{+}} x^{2}-24}{\lim _{x \rightarrow 5^{+}} x^{2}-25} \\
&=\frac{25-24}{25+-25} \\
&=\frac{1}{0^{+}}\\
&=\infty
\end{aligned}
