Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - Chapter Review Exercises - Page 95: 48



Work Step by Step

We evaluate the limit: \begin{aligned} \lim _{x \rightarrow 5^{+}} \frac{x^{2}-24}{x^{2}-25} &=\frac{\lim _{x \rightarrow 5^{+}} x^{2}-24}{\lim _{x \rightarrow 5^{+}} x^{2}-25} \\ &=\frac{25-24}{25+-25} \\ &=\frac{1}{0^{+}}\\ &=\infty \end{aligned}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.