Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.6 Trigonometric Limits - Exercises - Page 77: 21

Answer

$1$

Work Step by Step

\begin{align*} \lim _{x \rightarrow 0} \frac{ x^2}{\sin^2 x}&=\lim _{x \rightarrow 0} \frac{x}{\sin x}\frac{x}{\sin x}\\ &=\lim _{x \rightarrow 0} \frac{x}{\sin x}\lim _{x \rightarrow 0}\frac{x}{\sin x}\\\ &=1. \end{align*}
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