Answer
$0$
Work Step by Step
\begin{align*}
\lim _{t \rightarrow 0} \frac{ \sin^2 t}{t}&=\lim _{t \rightarrow 0} \frac{\sin t}{t}\sin t\\
&=\lim _{t \rightarrow 0} \frac{\sin t}{t}\lim _{t \rightarrow 0}\sin t\\
&=0.
\end{align*}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.6 Trigonometric Limits - Exercises - Page 77: 20
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
