Calculus (3rd Edition)

$f$ is squeezed by $u$ and $l$ at $x=3$. But $f$ is not squeezed by $u$ and $l$ at $x=2$.
We have $l(x) \leq f(x)\leq u(x)$ and since $\lim_{x\to 3}l(x)= \lim_{x\to 3}u(x)=1.5$, then by the squeeze theorem, we have $$\lim_{x\to 3}f(x)=1.5$$ and hence $f$ is squeezed by $u$ and $l$ at $x=3$. But $f$ is not squeezed by $u$ and $l$ at $x=2$, since $\lim_{x\to 2}l(x)\neq \lim_{x\to 2}u(x)$.