## Calculus (3rd Edition)

$\lim_{x\to 1}f(x)=2$
We have $l(x) \leq f(x)\leq u(x)$ and $\lim_{x\to 1}l(x)= \lim_{x\to 1}u(x)=2$ Then, by the squeeze theorem, we have $$\lim_{x\to 1}f(x)=2$$