Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - Chapter Review Exercises - Page 835: 13

Answer

$$-e^{-4}$$

Work Step by Step

Given $$\lim _{(x, y) \rightarrow(1,-3)}(2 x+y) e^{-x+y}$$ Since $ (2 x+y) e^{-x+y}$ is continuous, then \begin{align*} \lim _{(x, y) \rightarrow(1,-3)}(2 x+y) e^{-x+y}&=(2 \cdot 1-3) e^{-1-3}\\ &=-e^{-4} \end{align*}
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