Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.2 Limits and Continuity in Several Variables - Exercises - Page 772: 28



Work Step by Step

Given $$\lim _{(z, w) \rightarrow(-1,2)}\left(z^{2} w-9 z\right) $$ Since $ \left(z^{2} w-9 z\right) $ is continuous everywhere, then by substitution, we get \begin{align*} \lim _{(z, w) \rightarrow(-1,2)}\left(z^{2} w-9 z\right)&=\lim _{(z, w) \rightarrow(-1,2)}\left( 2+9\right)\\ &=11 \end{align*}
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