Answer
$0$
Work Step by Step
Since the function $ \ln(x-y)$ is continuous at $(1,0)$, then we have
$$ \lim\limits_{(x,y) \to (1,0)} \ln(x-y)=\ln(1-0)=\ln1=0.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 15 - Differentiation in Several Variables - 15.2 Limits and Continuity in Several Variables - Exercises - Page 771: 8
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