Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.2 Limits and Continuity in Several Variables - Exercises - Page 771: 6


$$\frac{\pi}{4} $$

Work Step by Step

Since the function $ \tan^{-1} (x^2- y)$ is continuous at $(2,3)$, then we have $$ \lim\limits_{(x,y) \to (2,3)}\tan^{-1} (x^2- y)=\tan^{-1} (2^2- 3)=\frac{\pi}{4} .$$
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