## Calculus (3rd Edition)

The equation can be rewritten in the form $$\left(\frac{x}{3}\right)^{2}-\left(\frac{y}{4}\right)^{2}+\left(\frac{z}{1/\sqrt{2}}\right)^{2}=1$$ which is a hyperboloid of one sheet. (See equations on page 691-692.)