Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - Chapter Review Exercises - Page 703: 57


Elliptic cone.

Work Step by Step

If we move the $z$ term to the right and rewrite the constant $2$ as a radical fraction, then the equation becomes $$ \left(\frac{x}{3}\right)^{2}-\left(\frac{y}{4 }\right)^{2} =\left(\frac{z}{1/\sqrt{2}}\right)^{2} $$ which is an elliptic cone.
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