Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.5 Planes in 3-Space - Exercises - Page 685: 38


$$ (-3,2,3)$$

Work Step by Step

The parametric equations of the line are given by $$ x=1-2t, \quad y=t, \quad z=1+t.$$ Now, substituting in the equation of the plane $$ x-y+5z=10\Longrightarrow 1-2t-t+5+5t=10\\ \Longrightarrow 2t=4\Longrightarrow t=2. $$ So the point of intersection is given by $$(1-2(2),2,1+2)=(-3,2,3).$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.