## Calculus (3rd Edition)

$$(4,3,2).$$
Assume that the terminal point of the vector $v = \langle 3, 2, 1\rangle$ is $(a,b,c)$. Then, we have $$\langle 3, 2, 1\rangle=(a,b,c)-(1,1,1)\Longrightarrow 3=a-1, \quad 2=b-1, \quad 1=c-1.$$ By solving the equations, we get the terminal point as follows $$(a,b,c)=(4,3,2).$$