Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 13 - Vector Geometry - 13.1 Vectors in the Plane - Exercises - Page 651: 71

Answer

See explanation

Work Step by Step

The angle between two non zero vectors is: $$\cos(\theta)=\frac{u\cdot v}{|u||v|}$$ Two vector are perpendicular if $\theta=\frac{\pi}{2}$ so: $$\cos(\frac{\pi}{2})=\frac{u\cdot v}{|u||v|}$$ $$0=\frac{u\cdot v}{|u||v|}$$ $$0=u\cdot v$$ Using the definition of the dot product it follows: $$0=ac+bd$$ Swap both sides: $$ac+bd=0$$
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