Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.1 Parametric Equations - Exercises - Page 604: 51

Answer

$$ \frac{d y}{d x}=\frac{3s^2}{-s^{-2}-3} $$ and at $s=-1$, we have $$ \frac{d y}{d x}=- \frac{3}{4}. $$

Work Step by Step

Since $x=s^{-1}-3s$ and $y=s^3$, then we have $$ \frac{d y}{d x}= \frac{y^{\prime}}{x^{\prime}}=\frac{3s^2}{-s^{-2}-3} $$ and at $s=-1$, we have $$ \frac{d y}{d x}=- \frac{3}{4}. $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.