Answer
$$ y =\tan^{-1} ( x^3+e^x) $$
Work Step by Step
Given $$ x=t,\ \ \ \ y=\tan^{-1} ( t^3+e^t),$$
Since $ t=x $, then
\begin{align*}
y&=\tan^{-1} ( t^3+e^t)\\
&=\tan^{-1} ( x^3+e^x)
\end{align*}
i.e.
$$ y =\tan^{-1} ( x^3+e^x) $$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.1 Parametric Equations - Exercises - Page 603: 9
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