Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 12 - Parametric Equations, Polar Coordinates, and Conic Sections - 12.1 Parametric Equations - Exercises - Page 603: 24

Answer

$$c(t)=(t,8t^2-3t)$$

Work Step by Step

To find parametric equations, we set $x=t$ and then we find $y=8t^2-3t$. So the given curve has the parametrization $$c(t)=(t,8t^2-3t)$$
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