Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 11 - Infinite Series - 11.4 Absolute and Conditional Convergence - Exercises - Page 563: 26

Answer

The series $\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{ (2n+1)!}$, converges.

Work Step by Step

For the series $\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{ (2n+1)!}$, the positive term $b_n=\frac{1}{ (2n+1)!}$ The terms are decreasing and positive. Evaluate the limit: $$\lim_{n\to \infty}b_n=\lim_{n\to \infty}\frac{1}{ (2n+1)!}=\frac{1}{\infty}=0$$ Thus, by the alternating series test, the series $\sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{ (2n+1)!}$, converges.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.