Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 11 - Infinite Series - 11.1 Sequences - Exercises - Page 537: 3


$$c_1=3, \quad c_2= \frac{9}{2}, \quad c_3= \frac{9}{2}, \quad c_4= \frac{27}{8} .$$

Work Step by Step

Since $c_n=\frac{3^n}{ n!}$, then we have $$c_1=\frac{3}{ 1!}=3, \quad c_2=\frac{3^2}{ 2!}=\frac{9}{2}, \quad c_3=\frac{3^3}{ 3!}=\frac{27}{6}=\frac{9}{2}, \quad c_4=\frac{3^4}{ 4!}=\frac{81}{24}=\frac{27}{8} .$$
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