Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 10 - Introduction to Differential Equations - Chapter Review Exercises - Page 526: 5


$$ y=cx-1.$$

Work Step by Step

By separation of variables, we have $$\frac{dy}{1+y}=\frac{dx}{x}$$ then by integration, we get $$ \ln(1+y)=\ln x+\ln c=\ln(cx) .$$ So the general solution is given by $$ y=cx-1.$$
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