Answer
$$ y=cx-1.$$
Work Step by Step
By separation of variables, we have
$$\frac{dy}{1+y}=\frac{dx}{x}$$
then by integration, we get
$$ \ln(1+y)=\ln x+\ln c=\ln(cx) .$$
So the general solution is given by $$ y=cx-1.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 10 - Introduction to Differential Equations - Chapter Review Exercises - Page 526: 5
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