Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 10 - Introduction to Differential Equations - 10.1 Solving Differential Equations - Exercises - Page 505: 29


$$y=C \sec t$$

Work Step by Step

\begin{align*} \frac{dy}{dt}&= y\tan y\\ \int \frac{1}{y} d y&=\int \tan t d t\\ \ln y&=\ln (\sec t)+\ln C\\ y&=C \sec t \end{align*}
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