#### Answer

$$y= \sin^{-1}(Ce^{\theta})$$

#### Work Step by Step

\begin{aligned}
\frac{d y}{d \theta} &=\tan y \\
\int \frac{1}{\tan y} d y &=\int d \theta \\
\ln \sin y&= \theta +C\\
y&= \sin^{-1}(Ce^{\theta})
\end{aligned}

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$$y= \sin^{-1}(Ce^{\theta})$$

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