Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 10 - Introduction to Differential Equations - 10.1 Solving Differential Equations - Exercises - Page 505: 28

Answer

$$y= \sin^{-1}(Ce^{\theta})$$

Work Step by Step

\begin{aligned} \frac{d y}{d \theta} &=\tan y \\ \int \frac{1}{\tan y} d y &=\int d \theta \\ \ln \sin y&= \theta +C\\ y&= \sin^{-1}(Ce^{\theta}) \end{aligned}
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