## Calculus (3rd Edition)

$$y-4=\frac{2}{3}(x+1)$$
The slope is given by $$m=\frac{6-4}{2-(-1)}=\frac{2}{3}$$ The equation of a line in point-slope form is: $y-y_1=m(x-x_1)$ Thus, the equation of the line is given by $$y-4=\frac{2}{3}(x-(-1))=\frac{2}{3}(x+1)$$