Answer
The equation is: $5x-3y-1=0$.
Work Step by Step
The slope of the given line is $\frac{-3}{5}$, and thus the slope of the perpendicular line is $\frac{5}{3}$. Hence, we have a slope and a known point $(2,3)$. So, the equation of the perpendicular line is (using point-slope form of a line):
$(y-y_1)=m(x-x_1)$
$(y-3) = \frac{5}{3} (x-2)$
and then
$3y-9=5x-10$
Thus, the equation is
$5x-3y-1=0$.
