## Calculus (3rd Edition)

The equation is: $5x-3y-1=0$.
The slope of the given line is $\frac{-3}{5}$, and thus the slope of the perpendicular line is $\frac{5}{3}$. Hence, we have a slope and a known point $(2,3)$. So, the equation of the perpendicular line is (using point-slope form of a line): $(y-y_1)=m(x-x_1)$ $(y-3) = \frac{5}{3} (x-2)$ and then $3y-9=5x-10$ Thus, the equation is $5x-3y-1=0$.