## Calculus (3rd Edition)

$7x+11y -51=0$ is the equation of the line passing through these points in question.
We can set up a slope ratio between the two points as follows: $\frac{y_{2} -y_{1}}{x_{2} -x_{1}} = slope = \frac{y-y_1}{x-x_1}$ (this is the point-slope form of a line, slightly rewritten.) Plugging in the given values, we get: $\frac{y-4}{x-1} = \frac{-3-4}{12-1}=\frac{-7}{11}$ We cross multiply and simplify: $11y -44 = -7x +7$ which gives $7x+11y -51=0$