Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.2 Linear and Quadratic Functions - Exercises - Page 18: 16


$7x+11y -51=0$ is the equation of the line passing through these points in question.

Work Step by Step

We can set up a slope ratio between the two points as follows: $\frac{y_{2} -y_{1}}{x_{2} -x_{1}} = slope = \frac{y-y_1}{x-x_1}$ (this is the point-slope form of a line, slightly rewritten.) Plugging in the given values, we get: $\frac{y-4}{x-1} = \frac{-3-4}{12-1}=\frac{-7}{11}$ We cross multiply and simplify: $11y -44 = -7x +7$ which gives $7x+11y -51=0$
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