Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 5


$\int u^{n}du$ $u=5x-3, n=4$

Work Step by Step

Try it: $du=5dx$ $\frac{1}{5} \int (5x-3)^{4}(5)dx$ $\frac{1}{5} \int u^{4}(5)du$ $\frac{1}{5}$($\frac{u^{5}}{5}+C)$ $\frac{1}{5}$($\frac{(5x-3)^{5}}{5}+C)$ ($\frac{(5x-3)^{5}}{25}+C)$ $\int u^{n}du$ $u=5x-3, n=4$
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