Answer
$\frac 1{4\pi}sin2\pi x^2+C$
Work Step by Step
$\int x(cos2\pi x^2)$
$u=2\pi x^2; du=4\pi xdx$
$\frac 1{4\pi} \int (cos2\pi x^2)(4\pi x)dx$
$\frac 1{4\pi}sin2\pi x^2+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 29
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