Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 17


$-\frac 7 {6(z-10)^6}+C$

Work Step by Step

$\int u^ndu =\frac {u^{n+1}}{n+1}$ $Let u=z-10; then du=dz$ $7 \int u^-7 du$ $7(\frac{u^{-6}}{-6}) +C$ $=\frac 7 {6u^6}+C$ $-\frac 7 {6(z-10)^6}+C$
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