Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.2 Exercises - Page 454: 47

Answer

$\frac{\pi}{6}$

Work Step by Step

$$ V = \pi \int_{0}^{1}[{(\sqrt{y})}^2-y^2]dy$$ $$ V = \pi \int_{0}^{1}[y-y^2]dy$$ $$ V = \pi [\frac{y^2}{2}-\frac{y^3}{3}]_{0}^{1}$$ $$ V = \pi[\frac{1}{6}]=\frac{\pi}{6}$$
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