Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 7 - Applications of Integration - 7.2 Exercises - Page 454: 25

Answer

$\frac{2\pi}{3}$

Work Step by Step

Setup the integration using disk method about the x-axis $\pi \int_1^3(\frac{1}{x})^2dx$ $\pi \int_1^3 (\frac{1}{x^2})dx$ $\pi[-\frac{1}{x}]_1^3$ $\pi(-\frac{1}{3}+1)$ $\frac{2\pi}{3}$
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