Answer
$$f'(x)=3^{x-1}\ln(3)$$
Work Step by Step
We know that $(a^{f(x)})'=\ln(a)a^{f(x)}f'(x)$
(by chain rule)
$f(x)=3^{x-1}$.
Therefore $f'(x) = ln(3)3^{x-1}(x-1)'=3^{x-1}\ln(3)$
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