Answer
True
Work Step by Step
$$f(e^{n+1})-f(e^n) = ln(e^{n+1})-ln(e^n) = (n+1)-n = 1$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 365: 112
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