Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.5 Exercises - Page 365: 109

Answer

$$e^2=7.389..$$

Work Step by Step

$9^{1/ln3} =(3^2)^{ln(e)/ln(3)} = 3^{2log_3e} = (3^{log_3e})^2 = e^2$ ($9 = 3^2; ln(e) = 1$; $ln(a)/ln(b) = log_ba; (a^m)^n =a^{mn} = (a^n)^m; a^{log_ab} = b$)
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