Answer
$-\frac{ln|cos(5θ)|}{5}+C$
Work Step by Step
$\int tan (5θ) dθ$
let $u=5θ$ $du= 5θ$
$dθ=\frac{1}{5}du$
$\int tan (5θ) dθ$
$=\frac{1}{5}\int tan (u)$ $du$
$=\frac{1}{5}(-ln|cos(u)|)+C$
$=-\frac{ln|cos(5θ)|}{5}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.2 Exercises - Page 334: 32
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
