Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 5 - Logarithmic, Exponential, and Other Transcendental Functions - 5.2 Exercises - Page 334: 32



Work Step by Step

$\int tan (5θ) dθ$ let $u=5θ$ $du= 5θ$ $dθ=\frac{1}{5}du$ $\int tan (5θ) dθ$ $=\frac{1}{5}\int tan (u)$ $du$ $=\frac{1}{5}(-ln|cos(u)|)+C$ $=-\frac{ln|cos(5θ)|}{5}+C$
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