Answer
$\frac{x^{2}}{2} - 4\ln|x|$ + C
Work Step by Step
$\int\frac{x^{2}-4}{x} dx $
= $\int(\frac{x^{2}}{x}-\frac{4}{x} )dx$
= $\int(\frac{x}{1}-\frac{4}{x} )dx$
= $\int x dx -\int\frac{4}{x}dx$
= $\frac{x^{2}}{2} - 4\int\frac{1}{x}dx$
= $\frac{x^{2}}{2} - 4\ln|x|$ + C
