Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - 3.5 Exercises - Page 202: 34

Answer

$0$

Work Step by Step

$\lim _{x\rightarrow -\infty }\dfrac {2x}{\left( x^{6}-1\right) ^{\frac{1}{3}}}=\dfrac {2x}{x^{2}\left( 1-\dfrac {1}{x^{6}}\right) ^{\frac {1}{3}}}=\dfrac {2}{x\left( 1-\dfrac {1}{x^{6}}\right) ^{\frac {1}{3}}}=\dfrac {2}{x\left( 1-0\right) ^{\frac {1}{3}}}=\dfrac {2}{x}=0$
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