Answer
$-\infty $
Work Step by Step
$\lim _{x\rightarrow -\infty }\dfrac {x^{3}-4}{x^{2}+1}=\dfrac {\dfrac {x^{3}}{x^{2}}-\dfrac {4}{x^{2}}}{\dfrac {x^{2}}{x^{2}}+\dfrac {1}{x^{2}}}=\dfrac {x-0}{1+0}=x=-\infty $
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 3 - Applications of Differentiation - 3.5 Exercises - Page 202: 26
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