$f(x)$ is concave up for all x ($-\infty < x < \infty$)
Work Step by Step
$f(x) = x^2 - x - 2$ 1.) Find $f''(x)$ $f'(x) = 2x - 1$ $f''(x) = 2$ Since $f''(x) > 0$ for $-\infty < x < \infty$, $f(x)$ is concave up for $-\infty < x < \infty$.
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.