Answer
$\dfrac{dy}{dx}=-\dfrac{3}{4}.$
Work Step by Step
$\dfrac{d}{dx}(x^2)+\dfrac{d}{dx}(y^2)=\dfrac{d}{dx}(C^2)\rightarrow$
$2x+\dfrac{dy}{dx}(2y)=0\rightarrow\dfrac{dy}{dx}=-\dfrac{x}{y}.$
When $ x=3 $ and $y=4 \rightarrow\dfrac{dy}{dx}=-\dfrac{3}{4}.$
